

You are using linear interpolation.ġ-D interpolation is an extremely well defined operation, and interp1 is a relatively straightforward interface for this operation. So, in your code, S(:,1) contains the sample points where your grid is defined, S(:,ii+1) contains your sampled values for your 1-D function, and U(ii,ii,:) contains the query points where you want to interpolate to find new functional values between known values in your grid. Vector xq contains the coordinates of the query points."

"Vector x contains the sample points, and v contains the corresponding values, v(x). You are using the syntax: vq = interp1(x,v,xq,method) I don't know scipy, but I can tell you what the interp1 call in MATLAB is doing: Temp.append(interpolate.interp1d( S, S, U)) ]
Matlab interp1 code#
However, the code has been implemented around 2010]. My Python version is 3.4.1, MATLAB version is R2013a. Could you tell me if the code, I implemented is correct? I found that the scipy function interp1d should be what I'm after, but I'm not sure. The code uses the function interp1 in MATLAB. I'm converting a MATLAB code into a Python code.
Matlab interp1 how to#
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